-4c^2+19c+5=0

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Solution for -4c^2+19c+5=0 equation:


Simplifying
-4c2 + 19c + 5 = 0

Reorder the terms:
5 + 19c + -4c2 = 0

Solving
5 + 19c + -4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + -1c)(1 + 4c) = 0

Subproblem 1

Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5

Subproblem 2

Set the factor '(1 + 4c)' equal to zero and attempt to solve: Simplifying 1 + 4c = 0 Solving 1 + 4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4c = 0 + -1 4c = 0 + -1 Combine like terms: 0 + -1 = -1 4c = -1 Divide each side by '4'. c = -0.25 Simplifying c = -0.25

Solution

c = {5, -0.25}

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